
#1
Nov1412, 05:12 PM

P: 2

I am designing a gear train for my basic mechanisms class that consists of three shafts. The input horsepower is 10 and rpm is 1750. I calculated the torque of the first shaft to be 360 but I am not sure if the horsepower stays the same throughout the whole train or not. The first shaft has a 14t gear meshing witha 40t gear on shaft two. Shaft two then has a 22t gear meshing with a 48t gear on shaft three for an output rpm of 281. In order to calculate the torque and force per tooth of each gear do I just use the input horsepower? Thanks in advance for any help.




#2
Nov1412, 06:56 PM

HW Helper
Thanks
P: 5,522

The torque will be multiplied (or reduced) depending on the ratio of gears between the input and output. Except for minor frictional losses in the geartrain, power in should be approx. the same as power out. (Welldesigned gear boxes usually have 23% loss).
For example, the first gear ratio is 40:14 or a ratio of 2.857 : 1. The input speed of 1750 rpm is slowed to 1750/2.857 = 612.5 RPM, and the input torque is multiplied to become 360*2.857 = 1028.6 inlb. 



#3
Nov1412, 07:07 PM

P: 2

So is the 1028.6 inlb the torque for the entire second shaft (the 40t and 22t gears) or the torque for the 40t gear alone? Thank you!




#4
Nov1512, 12:26 AM

HW Helper
Thanks
P: 5,522

Gear Train horsepower calculation
Assuming that the shaft connecting the 40t gear and the 22t gear is a regular shaft, the torque will be the same along the length. Look at it this way, if the 40t gear makes one revolution, the 22t gear will also make one revolution. There is nothing between the two gears which will cause the torque to decrease, except for minor frictional losses in the shaft bearings.



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