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Need quick help with Series, it will only take a few seconds! |
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| Nov27-12, 07:34 PM | #1 |
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Need quick help with Series, it will only take a few seconds!
So the differential equation I have to solve using power series is
y''-xy=0 when x0 = -1 So i set it up Ʃ(n+2)(n+1)an+2(x+1)n - x Ʃ an(x+1)n I know how to generally solve equations like this, but I never solved one like this, where I have to distribute the x ... x(x+1)n ... I just need to figure this part out (I know I left out the n=0 to ∞) |
| Nov27-12, 08:06 PM | #2 |
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Ok I figured it out using a cheap (but valid) math trick... in case anyone is wondering...
xƩan(x+1)n = (x+1-1)Ʃan(x+1)n Now the x+1 can be distributed to give -Ʃan(x+1)n+1 ...anyone care to double check me on this? |
| Nov27-12, 08:59 PM | #3 |
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