
#1
Nov2712, 07:34 PM

P: 25

So the differential equation I have to solve using power series is
y''xy=0 when x0 = 1 So i set it up Ʃ(n+2)(n+1)a_{n+2}(x+1)^{n}  x Ʃ a_{n}(x+1)^{n} I know how to generally solve equations like this, but I never solved one like this, where I have to distribute the x ... x(x+1)^{n} ... I just need to figure this part out (I know I left out the n=0 to ∞) 



#2
Nov2712, 08:06 PM

P: 25

Ok I figured it out using a cheap (but valid) math trick... in case anyone is wondering...
xƩa_{n}(x+1)^{n} = (x+11)Ʃa_{n}(x+1)^{n} Now the x+1 can be distributed to give Ʃa_{n}(x+1)^{n+1} ...anyone care to double check me on this? 



#3
Nov2712, 08:59 PM

HW Helper
P: 1,391




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