# How is this torsion?

by Femme_physics
Tags: torsion
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PF Gold
P: 6,048
 Quote by Femme_physics There is shearing according to the solution. 1st) Shearing 2nd) Torsion Sorry for the img being so big. Essentially we got combined forces here.
That is really big, indeed. Sorry for my response also being of the same order of magnitude in size. I want to point out that in your formula $ρ_s = F/\Sigma l$, that is the formula for the vertical shear in the weld in units of force per length of weld. It should not be confused with the shear stress in the beam. As has been pointed out, both the beam and welds are subject to bending and shear stresses from forces and and moments. Both the beam and weld must be designed accordingly, so don't confuse the 2.
 P: 699 That's an awful lot of correspondence and really it's just the use of terms and a point of view. The weld group is subjected to a tension, a shear and a moment about the centroid of the weld group, about the axis perpendicular to the paper. If someone wants to call that moment a torsion, why shouldn't they? It's not a bad use of the term in this case, because it causes shear stresses in the welds, and shear stress is usually associated with torsion in a solid member. What it does not represent is a torsion on the beam itself. That is bending. But we are discussing the weld group...
PF Gold
P: 2,551
 In the picture I drew, there is a combination of bending and torsion.
Yes, however in the original exercise we didn't take bending into account, how come?