
#1
Dec612, 07:24 AM

P: 20

I am right now studying Rigid Body dynamics..
I have some doubts regarding Dynamics... 1) When a body is rotating as well as translating....we say that every particle of the ..lets say ROD is moving with a resultant velocity = Vcm ( translational velocity of COM) + ω.R (where R is the distance from COM ) ( ω is angular velocity..) My doubt is that how do we knw that every particle of the rod is translating with a velocity with which the COM is Translating... 2) My sir told that ω of a body is same whatever be the axis of rotation .. And thats why we very effectively use the Angular Momentum conservation theorem .. 



#2
Dec612, 07:37 AM

P: 110





#3
Dec612, 08:08 AM

P: 20





#4
Dec612, 11:12 PM

Homework
Sci Advisor
HW Helper
Thanks ∞
P: 9,215

Rotational Dynamics Confusion...If you inspect one particle of the body at some instant, without reference to any other parts of it, it will have a position. if you inspect it for a slightly longer instant, you discover it has a velocity. In isolation, there is no basis for breaking the velocity up into a translational and rotational velocity. That said, if you study for a yet longer instant, you'll find it has an acceleration, and you could choose to distinguish the component of the velocity orthogonal to the acceleration as 'rotational', but I'm not sure that makes sense in general. If the body as a whole is not being subjected to a net force then its CoM will have no acceleration. If it is rotating about a steady axis, those particles on the axis will have the same velocity as the CoM. The velocity of a particle of a rigid body in general will have a velocity v equal to v_{c}+ω x r, where v_{c} is the velocity of the mass centre, ω is the rotation vector and r is the position vector of the particle relative to the mass centre. That is the consequence of the fact that it is a rigid body. This does provide a basis for thinking of the particle's velocity as composed of those two components, but it's only a way of viewing things. 



#5
Dec712, 07:54 AM

P: 20

So here we study the motion of centre of mass of the body and letz say it has a velocity Vcm ..then we know that the whole body has a translational velocity Vcm.... But letz say that at some instant i obtained the net velocity of a particle say V...then the translational velocity of the body will be V(translational) = Net velocity  ω.R (R=Distance from COM)... I hav one mOre question.....Why dont we consider the rotation of COM.. Does COM have an angular velocity ω ... Or is it that we study the motion w.r.t the COM and hence it does not have angular velocity and all other particles have their angular velocity measured w.r.t COM..??? .. 



#6
Dec712, 08:24 AM

Sci Advisor
HW Helper
Thanks
P: 26,167

Hi D_DaYwAlKeR!
We don't have to start with the c.o.m., we can start with any point P, the velocity of any other point X is then v_{P} + ω x PX (after all, velocity of a rigid body is just geometry … 



#7
Dec712, 08:39 AM

P: 20

@tinytim
THnxx... Ok. So Since in most of the cases Bodies rotate along the COM axis ..that's why we study rotation with respect to COM...and that's why particles other than COM have angular velocity while COM only translates...More over its easy to calculate Moment of Inertia along COM axis...Am i correct here/???? Now if choose to study the motion with respect to some other axis passing through a point P on the body ...then with respect to that axis the point P will have no angular velocity while other particles including COM have angular as well as translational velocity.,.. Am i correct here??... 



#8
Dec712, 09:08 AM

Sci Advisor
HW Helper
Thanks
P: 26,167

we study rotation wrt the c.o.m. because usually the c.o.m is the only point whose velocity we know (we get it from F = ma_{c.o.m} ) (the exception is where one point is fixed, eg a pivot or a rolling point of contact … ie, it's the instantaneous centre of rotation … then obviously it's easier to use that point!) we can always apply the parallel axis theorem to get the moment of inertia about the centre of rotation instead 



#9
Dec712, 09:17 AM

P: 20

...and that's why particles other than COM have angular velocity while COM only translates
By this I meant that when we study motion w.r.t COM, then COM will only have translational velocity whereas all other particles will have velocity = Vcm + w.R ...and COM will have no tangential velocity as V(tangential) = w.R (R here is 0)... Whatever axis we choose that point of the body will have w.R = 0 .. Am i correct???... Thnxxx a lot @tiny  tim .. haruspex DeIdeal .. You all helped a lOT...:)..:) 



#10
Dec712, 09:25 AM

Sci Advisor
HW Helper
Thanks
P: 26,167

(but it's all just maths, not physics … i'd forget the explanation, and just use the formula ) 



#11
Dec712, 09:37 AM

P: 20

@tiny tim ...Thnxx A lot mate!...
u cleared all my doubts ... 


Register to reply 
Related Discussions  
Fluid Dynamics Confusion  Mechanical Engineering  3  
Fluid Dynamics Confusion  Classical Physics  4  
rotational dynamics confusion. help please  Introductory Physics Homework  5  
Rotational Equilibrium and Rotational Dynamics problem  Introductory Physics Homework  1  
Rotational Equilibrium and Rotational Dynamics  Introductory Physics Homework  1 