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please help transistor amplifier

 
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Dec19-12, 09:50 AM   #188
 

please help transistor amplifier


Quote by Jony130 View Post
No the design is good. Simply the BJT that michael1978 use in his simulation has a very low current gain.
Ie = 0.4V/220Ω = 1.8mA

And Ib = IR4 - IR5

IR4 = 1V/30K = 33.4μA

IR5 = (10V - 1V)/150kΩ = 9V/150KΩ = 60μA

So Ib = 60μA - 33.4μA = 26.6μA

And Hfe = β = (Ie/Ib - 1) = 66.6

And this circuit was design for Hfe > 420
so result is correct 66.6, for ib like this is formula for current Ir5-Ir4? is not the same for ir4 and ir5 they are in serie ir4 and ir5
but Jony you told Ve to be 1v why is now Ve 0.4V?
thnx for reply
 
Dec20-12, 05:36 AM   #189
 
Quote by michael1978 View Post
so result is correct 66.6, or voltage gain is 66.6, if so 66.6*2Mv=133mv again the result is not corrcect
for ib like this is formula for current Ir5-Ir4? is not the same for ir4 and ir5 they are in serie ir4 and ir5
but Jony you told Ve to be 1v why is now Ve 0.4V?
thnx for reply
thnx for reply
]so result is correct 66.6, or voltage gain is 66.6, if so 66.6*2Mv=133mv again the result is not corrcect
for ib like this is formula for current Ir5-Ir4? is not the same for ir4 and ir5 they are in serie ir4 and ir5
but Jony you told Ve to be 1v why is now Ve 0.4V?
thnx for reply[/QUOTE]
thnx for reply
 
Dec22-12, 05:41 PM   #190
 
Quote by michael1978 View Post
thnx for reply
]so result is correct 66.6, or voltage gain is 66.6, if so 66.6*2Mv=133mv again the result is not corrcect
for ib like this is formula for current Ir5-Ir4? is not the same for ir4 and ir5 they are in serie ir4 and ir5
but Jony you told Ve to be 1v why is now Ve 0.4V?
thnx for reply
thnx for reply[/QUOTE]

hi Jony, can you answer me please
 
Dec23-12, 07:14 AM   #191
 
Quote by michael1978 View Post
thnx for reply
]so result is correct 66.6, or voltage gain is 66.6, if so 66.6*2Mv=133mv again the result is not corrcect
for ib like this is formula for current Ir5-Ir4? is not the same for ir4 and ir5 they are in serie ir4 and ir5
but Jony you told Ve to be 1v why is now Ve 0.4V?
thnx for reply
66 is a BJT current gain, not a amplifier voltage gain.
So in order to make this circuit work properly. You need change the BJT that you use in your simulation program. You need to find the BJT with Hfe > 300 in your simulation.
 
Dec23-12, 08:26 AM   #192
 
Quote by Jony130 View Post
66 is a BJT current gain, not a amplifier voltage gain.
So in order to make this circuit work properly. You need change the BJT that you use in your simulation program. You need to find the BJT with Hfe > 300 in your simulation.
ah 66 is curent gain, so you mean to change type of transistor, but is possible for you to tell me any type of transistor wich work, because there are a lot of type of transistor, and somebody he tell me one type of transistor but that transistor dont exist in my list of transistors
and yes Jony if you can tell me, i try to find self soms but i cant find it, that is the problem
thnx for reply
 
Dec23-12, 08:35 AM   #193
 
BC548C
What simulation program do yo use ?
 
Dec23-12, 08:44 AM   #194
 
Quote by Jony130 View Post
BC548C
What simulation program do yo use ?
o joney i dont have, i have bc548A but not BC548C, i use B2 Spice A/V
 
Dec23-12, 09:00 AM   #195
 
hey Jony i try with bc548A, and i get voltage gain of 84mv is this correct?
 
Dec23-12, 09:03 AM   #196
 
Use BC547C
 
Dec23-12, 09:10 AM   #197
 
Quote by Jony130 View Post
Use BC547C
yes Joney i have that type i change, and now voltage gain is 94mv is correct now?
 
Dec23-12, 09:56 AM   #198
 
Well first you need to learn how to use the simulation program.
I use B2 Spice V5 and as a BJT use BC547C. And AC sweep analysis show that voltage gain is equal to 50.1V/V
For 20mV at input I get 1V at output.
Attached Thumbnails
aa.PNG   aa2.PNG  
 
Dec23-12, 10:10 AM   #199
 
Quote by Jony130 View Post
Well first you need to learn how to use the simulation program.
I use B2 Spice V5 and as a BJT use BC547C. And AC sweep analysis show that voltage gain is equal to 50.1V/V
For 20mV at input I get 1V at output.
but this was disegn for 10v battery not 12v
 
Dec23-12, 10:22 AM   #200
 
Well for Vcc = 10V the voltage gain is equal to 46V/V (0.9V at output for 20mV at input) because we don't included RL in our calculations when we solve for Re2.
Attached Thumbnails
aa12.PNG  
 
Dec23-12, 11:00 AM   #201
 
Quote by Jony130 View Post
Well for Vcc = 10V the voltage gain is equal to 46V/V (0.9V at output for 20mV at input) because we don't included RL in our calculations when we solve for Re2.

my circuit look like this
 
Dec23-12, 11:13 AM   #202
 
If so, your voltage gain is equal to 46V/V
 
Dec23-12, 11:15 AM   #203
 
my circuit look like this , the voltage gain is correct almost the same like yours, but metter gain is not correct, WHY GAIN METTER NOT CORRECT
Attached Thumbnails
Screenshot - 23_12_2012 , 18_09_32.png  
 
Dec23-12, 11:18 AM   #204
 
Quote by Jony130 View Post
If so, your voltage gain is equal to 46V/V
yes almost 2Mv*46=92MV my 94MV
 
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