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Mass of the moon?

by wasi-uz-zaman
Tags: mass, moon
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wasi-uz-zaman
#1
Dec30-12, 06:53 AM
P: 40
hi, i can calculate the distance of moon from the earth and its diameter - but i could't get the formula by which i can calculate the mass of the moon - although i can calculate the mass of the moon by assuming it has same average density that of earth -
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mfb
#2
Dec30-12, 08:11 AM
Mentor
P: 11,819
The orbital period of the moon depends on its distance and the sum of masses of earth and moon - if you can determine this sum with sufficient precision, you can subtract the mass of earth and get the mass of moon.
Satellites orbiting the moon are a better way to determine its mass - they give direct access to the gravitational acceleration at a specific distance, together with the gravitational constant this can be used to calculate its mass.
wasi-uz-zaman
#3
Jan2-13, 11:37 AM
P: 40
but how do i calculate the sum of earth and moon mass?

mfb
#4
Jan2-13, 11:59 AM
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P: 11,819
Mass of the moon?

Measure distance, orbital period and the gravitational constant.

##M+m=\frac{4\pi^2a^3}{GT^2}## with the semi-major axis a (for a circular orbit, this would be the distance)
BobG
#5
Jan4-13, 07:28 PM
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I'm curious as to how you calculated the distance between the Moon and Earth. That distance might not be the semi-major axis of the Moon's orbit. It might be the sum of the Moon's semi-major axis and the Earth's semi-major axis, as measured from their combined center of mass. (The 'a' in the previous equation is actually the sum of the semi-major axes, or the distance you most likely calculated.)

In practice, calculating the mass and the semi-major axis of planets was an almost impossible task even after Newton turned Kepler's Third Law into a formula. You had a formula containing three unknown variables (the universal gravitational constant, the mass, and the semi-major axis) and the only known was the orbital period.

In fact, that's why the Earth's semi-major axis for it's orbit around the Sun was measured in astronomical units, with one AU being the distance between the Sun and the Earth. You could measure Jupiter's semi-major axis in AU's, but had no way to convert that into a more traditional measure such as kilometers.


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