
#1
Jan1513, 07:47 AM

P: 173

If pi is infinite and nonrepetive and every number combination is in pi, somewhere, does that mean pi itself is in pi somewhere.. ? (that would make it periodic)




#2
Jan1513, 08:08 AM

Sci Advisor
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P: 4,301

Yes, it is, starting at the first digit :)




#3
Jan1513, 08:32 AM

P: 744

There can only be countably many nonterminating decimal expansions found in consecutive digits in the decimal expansion of pi  the one starting at the first digit, the one starting at the second digit, the one starting at the third digit, etc. Since there are uncountably many nonterminating decimal expansions, it is certain that not all of them appear. 



#4
Jan1513, 02:14 PM

P: 150

Pi inside pi inside pi .. 



#5
Jan1513, 02:19 PM

P: 7

The string 31415926 occurs at position 50,366,472 counting from the first digit after the decimal point.
http://www.angio.net/pi/bigpi.cgi 



#6
Jan1513, 02:24 PM

P: 744





#7
Jan1513, 03:11 PM

P: 824

[itex]\pi[/itex] is not periodic. If it were it would be in [itex]\mathbb{Q}[/itex] which it isn't.




#8
Jan1513, 06:21 PM

Math
Emeritus
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PF Gold
P: 38,879

Edi, it is NOT known whether "every number combination is in pi" is true or not. 



#9
Jan1613, 10:32 AM

P: 832

You are looking for a number n such that 10^n*pipi is an integer. Call this integer q.
Then (10^n1)*pi = q pi = q/(10^n1) To find such an n, pi would have to be a rational number, which is isn't. So, no, pi cannot repeat or contain itself. 



#10
Jan1613, 11:45 AM

P: 744





#11
Jan1613, 06:34 PM

P: 832

you know what I meant.




#12
Jan1713, 02:42 AM

Sci Advisor
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P: 4,301





#13
Jan1713, 07:24 AM

P: 744

Well, I could be even more picky and take n = 0.1200175... and q = 1.



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