Terning a text based problem into a number based problem

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Turning a text-based problem into a number-based problem involves identifying variables and systematically translating each sentence into equations. Start by determining how many variables are present and assign distinct names to avoid confusion. Each statement in the problem can be converted into a corresponding equation, ensuring clarity in the relationships between the variables. Solving the equations step-by-step allows for easy reference back to the original problem. This methodical approach helps simplify complex worded problems into manageable mathematical expressions.
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Turning a text based problem into a number based problem

I can solve these types of questions such as:

4(3x-5)=5x+2(x+15)

but when a question is worded something like:

"The second of three numbers is 1 less than the first. The third number is 5 less than the second. If the first number is twice as large as the third, find the three numbers."

There is just too much going on in that worded problem for me to be able to express it differently.

A simple question like:

"A can of beans weighs twice as much as a can of coke plus 2lbs"

This is simple, I can just say:

b = 2c + 2

But the questions in my book are just so long winded -_- any tips?
 
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Just take it slow and be systematic. The first clue you are looking for is how many variables are there - which is three. Then you assign them names, eg. a, b and c. Then just write down the equations as they come along. For instance, the first sentence also tells you that b=a-1, and so on.
 


Restless said:
The second of three numbers is 1 less than the first.
The third number is 5 less than the second.
If the first number is twice as large as the third,
find the three numbers.

You might want to choose names that you can't mix up part way through the problem.
First step might be this, to avoid using x for first and then later x for second or third.
Each sentence is turned directly into a single simple equation with appropriate names.

second= -1+first
third= -5+second
first= 2*third

Then if you need to the next step might be this

s=f-1
t=s-5
f=2*t

and solve that.

When you get something like s=4, t=2, f=5 you can look back at your original problem and see exactly what each of those results should be used for.

Just be careful to not mix up s and 5 or o and 0 or l and 1, etc.
 
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