Are Dirac Spinors Indicating Two Particles in Your Solution?

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    Dirac Spinors
ChrisVer
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Hello. I would like to ask something that will help me understand a little better how we work with Dirac spinors' inputs...
I know that the dirac equation has 4 independent solutions, and for motionless particles, the (spinor) solutions are:
u_{+}=(1,0,0,0)^{T} electron +1/2
u_{-}=(0,1,0,0)^{T} electron -1/2
v_{+}=(0,0,1,0)^{T} positron +1/2
v_{-}=(0,0,0,1)^{T} positron -1/2

Now suppose that I write a solution as:
Ψ=(1,0,0,1)^{Τ}
Does that mean that I'm having 2 particles (one positron and one electron) involved?
 
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In the single-particle first quantized theory, the four components of the spinor represent particle states with spin ±ħ/2 and energy ±E. So just as ψ = (1,1,0,0) represents a state with equal probability of the particle having spin up and down, so ψ = (1,0,0,1) represents a state with equal probability of the particle having spin up energy +E, and spin down energy -E. In the framework of this theory there is no antiparticle.
 
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