Load Displacement to stress strain

[8-)]

Hello, so here is my problem.

Homework Statement

I am given tensile data, which is displacement (mm) and load (kgf). also I am given width(mm), thickness(mm), gauge length (mm) and cross-head speed (mm/min). How do i make a stress strain curve from this?

The Attempt at a Solution

So far i have multiplied width by thickness to find cross sectional area (in metres squared). Then i divide load (kgf) *9.8/cross sectional area (m^2) to find stress. and displacement (metres) over gauge length (metres) to find strain. I am getting around 65,000,000 pascals for maximum stress at around 40% strain. its for PVC. does that make sense?

thanks!

 

[pongo38]

not compared with steel whose weakest strength would be around 250,000 pascals. (Check this yourself from some independent source)

 

[8-)]

Yeah it seemed off, where am i messing up?

 

[john.phillip]

If you search www.matweb.com for PVC, and read the material specs carefully, you may find data to compare with your results.

 

[DeeNos]

Hello, thank you for reaching out about your problem. It seems like you are on the right track in creating a stress-strain curve from the given data. The method you described is commonly used to calculate stress and strain from load and displacement data in tensile testing. However, it is important to note that the resulting stress-strain curve may not be entirely accurate due to the limitations of the data provided. For example, the cross-head speed may affect the accuracy of the results, as well as any potential errors in measuring the dimensions of the sample. Additionally, the properties of PVC may vary depending on the specific composition and manufacturing process. It may be helpful to compare your results with published data on PVC stress-strain curves to ensure accuracy. Overall, your approach seems reasonable and it is important to consider the limitations and potential sources of error in your analysis. I hope this helps and good luck with your project!