- #1
HeyHow!
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i have been give the equation
f(x) = 1/(x+3) + 1/(x-1)
i am trying to find the stationary points. so
f '(x) = -1/(x+3)^2 -1/(x-1)^2
f '(x) = 0 for stationary point
then when i simplified down i get 2x^2+4x+5 = 0, which is undefinable
i looked at the derivative on the graph and it looks like it has a turning point at (-1,0).
please help, either i have made an easy mistake or somethings wrong!
f(x) = 1/(x+3) + 1/(x-1)
i am trying to find the stationary points. so
f '(x) = -1/(x+3)^2 -1/(x-1)^2
f '(x) = 0 for stationary point
then when i simplified down i get 2x^2+4x+5 = 0, which is undefinable
i looked at the derivative on the graph and it looks like it has a turning point at (-1,0).
please help, either i have made an easy mistake or somethings wrong!