- #1
Bipolarity
- 776
- 2
For a reversible process, I imagine it is correct to say that
[itex] dS = \frac{dq}{T} [/itex] where all quantities refer to system quantities (not the surrounding).
However, for an adiabatic process, [itex] dq = 0 [/itex].
Thus, should it be the case that for an adiabatic reversible process,
[itex] dS = \frac{dq}{T} = \frac{0}{T} = 0 [/itex]
Please correct me if I am wrong, and point out the flaws in my reasoning.
BiP
[itex] dS = \frac{dq}{T} [/itex] where all quantities refer to system quantities (not the surrounding).
However, for an adiabatic process, [itex] dq = 0 [/itex].
Thus, should it be the case that for an adiabatic reversible process,
[itex] dS = \frac{dq}{T} = \frac{0}{T} = 0 [/itex]
Please correct me if I am wrong, and point out the flaws in my reasoning.
BiP