- #1
franky2727
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revising for a text and got stuck mid way through a question
Find the eigenvalues and vectors of A (in matrix form i will state colum then column then column) A((3,0,0),(0,2,0),(0,0,2) B=((3,0,0),(0,2,1),(0,0,2)
for A i got x(lamda)=(lamda-3)(lamda-2)^2 lamda=2or3
then i got lamda=3 solved to get a non zero multiple of (1,0,0)
its the second bit that I am stuck on my notes tell me that lamda=2 gives eigenvectors (a,a,b) where a and b are any reals, i don't get why this is a,a,b) and not (a,b,b,) usualy i would just think this is a mistake in my copying down but i remember the teacher explaining why it was 11b and not abb just can't remember why, if someone could shed some light this would be much apprichiated, thanks
Find the eigenvalues and vectors of A (in matrix form i will state colum then column then column) A((3,0,0),(0,2,0),(0,0,2) B=((3,0,0),(0,2,1),(0,0,2)
for A i got x(lamda)=(lamda-3)(lamda-2)^2 lamda=2or3
then i got lamda=3 solved to get a non zero multiple of (1,0,0)
its the second bit that I am stuck on my notes tell me that lamda=2 gives eigenvectors (a,a,b) where a and b are any reals, i don't get why this is a,a,b) and not (a,b,b,) usualy i would just think this is a mistake in my copying down but i remember the teacher explaining why it was 11b and not abb just can't remember why, if someone could shed some light this would be much apprichiated, thanks