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Homework Statement
A solenoid has 1800 turns of wire and is 125 cm long and 10.0 cm in diameter; see Figure P.14 (attached). A circular wire loop of diameter 5.0 cm lies along the axis of the solenoid near the middle of its length as shown.
(a) If the current in the solenoid initially is 4.0 A, find the magnetic flux through the smaller loop.
(b) If the current in the solenoid is switched off and falls to zero in 3.0 s, calculate the average value of the emf induced in the smaller loop.
Homework Equations
1. B(inside solenoid) = [tex]\mu[/tex]0*n*I, where n=number turns, I= current
2. [tex]\Phi[/tex]magnetic=[tex]\int[/tex][tex]\stackrel{\rightarrow}{B}[/tex]*[tex]\stackrel{\rightarrow}{dA}[/tex]
The Attempt at a Solution
[tex]\Phi[/tex]magnetic=[tex]\int[/tex][tex]\stackrel{\rightarrow}{B}[/tex]*[tex]\stackrel{\rightarrow}{dA}[/tex] = BA = B*[tex]\pi[/tex]*r2 (this did not work, and as I did not get the first part, I had no idea how to even approach the second part...thanks for any advice).