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tayyabah1415
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Homework Statement
Could someone please help me with this quesiton
4. The Earth revolves about its axis every 24 hours. Find the magnitude of the average acceleration of a point on
the equator over a 5-hour time interval. (The radius of the Earth is 6.38 x 106 m.)
Homework Equations
A = V^2/R
A = 4pi^2*R/T^2
A = 4pi^2 * R * f*2
The Attempt at a Solution
ok I am not quite sure what to do but this is what i have done so far
T = 24h or 86400s
R = 6.38 x 10^6
A= 4pi^2 * (6.38 x 10^6)/(24h)^2
A = 437278.31m/h^2
so i am guessing that's the acceleration per hour
for 7 hours it would be
437278.31m/h^2 * 7h = 3.06 x10^6m/h
this is where i get confused I am pretty sure I am supposed to have m/h^2 in the answer but i have m/h
please help or explain what i am doing wrong