- #1
pivoxa15
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They claim that the trivial 0s (zeta(z)=0) occur when z is a negative odd integer (with no imaginary component). But it seems obviously wrong.
Take z=-2
zeta(-2)=1+1/(2^-2)+1/(3^-2)...
=1+4+9...
Obviously this series will not equal 0.
Where have I gone wrong?
Have I misunderstood the meaning of 'zeros of the zeta function'?
Take z=-2
zeta(-2)=1+1/(2^-2)+1/(3^-2)...
=1+4+9...
Obviously this series will not equal 0.
Where have I gone wrong?
Have I misunderstood the meaning of 'zeros of the zeta function'?
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