- #1
Chemist20
- 86
- 0
the following?:
low-spin d5 metal. Energy = -2Δ -4K (where K is exchange energy. i,e. minimization of energy due to parallel spins)
low-spin d6 metal. Energy = -1.6Δ -3K
Therefore: energy needed to add an electron = ΔE= 0.4Δ + K
Is that correct?
maybe I should be talking about Spin Pairing Energy (P) ...
HEEEEEEEEEEEEEEEEEEEEEEEEEEEELP!
low-spin d5 metal. Energy = -2Δ -4K (where K is exchange energy. i,e. minimization of energy due to parallel spins)
low-spin d6 metal. Energy = -1.6Δ -3K
Therefore: energy needed to add an electron = ΔE= 0.4Δ + K
Is that correct?
maybe I should be talking about Spin Pairing Energy (P) ...
HEEEEEEEEEEEEEEEEEEEEEEEEEEEELP!