What is the distance needed for a rocket to reach a velocity of 0 on Planet X?

In summary, the conversation discussed the concept of escape velocity on Planet X and how it relates to the distance the rocket needs to be in order to achieve a velocity of 0. The steps to solving this problem were also mentioned, as well as a hint given by the professor. There was a discussion about whether this was a trick question or not, and the answer was ultimately that the rocket would need to be at a distance of 0 from the center of Planet X.
  • #1
scoop91
4
0
The escape velocity on Planet X is the speed the rocket needs in order to never fall back down again in a universe in which X is the only object. In order for the rocket to not fall back down, its velocity to never become negative, how far away does the rocket have to be when the velocity is 0?

What are the steps to solving a problem such as this one?
 
Astronomy news on Phys.org
  • #2
Welcome to PF!

There's nothing to solve there, it is just a matter of understanding the implications of escape velocity. I'd start by reading the wiki on it...
 
  • #3
So all in all, it ends up being a trick question? Lol
 
  • #4
scoop91 said:
So all in all, it ends up being a trick question? Lol

It depends if the speed is the rocket or the rocket is the speed or some weird quantum superposition of speed/rocket states.
 
  • #5
bp_psy said:
It depends if the speed is the rocket or the rocket is the speed or some weird quantum superposition of speed/rocket states.

Our prof gave us a hint and told us to call the position Xf. He indicated that the answer was right under our noses.

Which led me to believe that there was some deception involved.
 
  • #6
scoop91 said:
So all in all, it ends up being a trick question? Lol
I don't see it as a trick question, no. This is a common question people have/don't understand regarding escape velocity.

Did you find the answer?
 
  • #7
According to the escape velocity equation, the distance from the centre of Planet X would need to be infinite to achieve a velocity of 0. It could always reverse it's thrust to achieve a velocity of 0, but the question says it can't. OR considering the definition of escape velocity and the common misconceptions, the answer is probably the rocket would have to be inside the planets centre, where r = 0.
 
Last edited:

1) What is escape velocity on Planet X?

Escape velocity on Planet X is the minimum velocity required for an object to escape the gravitational pull of the planet and enter into an orbit around it.

2) How is escape velocity calculated on Planet X?

The formula for escape velocity on Planet X is given by v = √(2GM/R), where G is the gravitational constant, M is the mass of Planet X, and R is the radius of the planet.

3) Does escape velocity on Planet X vary for different objects?

Yes, escape velocity on Planet X will vary for different objects depending on their mass and distance from the planet. Objects with greater mass will require a higher escape velocity to overcome the planet's gravitational pull.

4) How does the escape velocity on Planet X compare to other planets?

The escape velocity on Planet X will depend on the mass and radius of the planet. Generally, planets with greater mass and larger radii will have a higher escape velocity. For example, the escape velocity on Earth is 11.2 km/s while on Jupiter it is 59.5 km/s.

5) Why is escape velocity important on Planet X?

Escape velocity is important on Planet X because it determines whether or not an object can escape the planet's gravitational pull. It is crucial for space exploration and understanding the dynamics of objects in orbit around the planet.

Similar threads

  • Introductory Physics Homework Help
Replies
7
Views
87
Replies
13
Views
8K
  • Astronomy and Astrophysics
Replies
4
Views
2K
  • Introductory Physics Homework Help
Replies
7
Views
1K
  • Astronomy and Astrophysics
Replies
5
Views
963
Replies
21
Views
4K
  • Introductory Physics Homework Help
Replies
1
Views
889
  • Astronomy and Astrophysics
Replies
4
Views
2K
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
8
Views
1K
Back
Top