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Homework Statement
A ten pound car wheel has a moment of inertia of .35 kgm^2. While rotating at a constant speed the wheel makes 87.61 revolutions in 5.42s. How much torque is required to stop the wheel in 41.2 s?
Homework Equations
The Attempt at a Solution
87.61rev/5.42sec = 16.164 rev/sec x 2pi = 101.56 rad/s / 41.2 sec = 2.465 rad/s^2
t= .35 kgm^2 x -.2.465 = -.8675 m x n?
not sure how relevant all of the steps i did are but that is where i stopped... any help?