- #1
BrainHurts
- 102
- 0
Is there one?
I know A=[1 1;0 1] and A-1=[1 -1;0 1]
So I know that A and A-1 have the same eigenvalues, I know that this is not sufficient to say that A and A-1 are similar (or maybe) but the dimension of the Eigenspace with eigen value 1 is 1.
In other words the geometric multiplicity does not equal the algebraic multiplicity.
So does this ultimately mean that A and A-1 are not similar?
I know A=[1 1;0 1] and A-1=[1 -1;0 1]
So I know that A and A-1 have the same eigenvalues, I know that this is not sufficient to say that A and A-1 are similar (or maybe) but the dimension of the Eigenspace with eigen value 1 is 1.
In other words the geometric multiplicity does not equal the algebraic multiplicity.
So does this ultimately mean that A and A-1 are not similar?