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miamirulz29
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Homework Statement
It takes 3.23 J of work to stretch a Hooke's-law spring 12.1 cm from its unstressed length. How much extra work is required to stretch it an additional 5.76cm. Answer in Joules.
Homework Equations
F= -kx
W= FD
The Attempt at a Solution
At first, I try using proportions to do this problem:
3.23/12.1 = x/5.76
I got that answer but it was wrong.
So I tries finding the force using w=fd. Then I multiplied that by 5.76 and I got the same answer as doing it the proportion method.
What am I doing wrong. Do I need K or do I need to use the equation W = 1/2kx^2? Thanks in advance.