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Elastic Potential Energy of Elastic Band*
A stretched elastic band of mass 0.55 g is released so that its initial velocity is horizontal, and its initial position is 95 cm above the floor. What was the elastic potential energy stored in the stretched band if, when it lands, it has a horizontal displacement of 3.7 m from the initial position under negligible air resistance?
vf^2 = vi^2 + 2ad
Ee = Ek - Eg
vf^2 = vi^2 + 2ad
0 = vi^2 + 2ad
2(9.8)(0.95) = vi^2
4.32 m/s = vi
Ee = Ek - Eg
Ee = 0.5mv^2 - mgh
Ee = (0.5)(0.55)(4.32)^2 – (0.55)(9.8)(3.7)
Ee =
I get a negative number?
Homework Statement
A stretched elastic band of mass 0.55 g is released so that its initial velocity is horizontal, and its initial position is 95 cm above the floor. What was the elastic potential energy stored in the stretched band if, when it lands, it has a horizontal displacement of 3.7 m from the initial position under negligible air resistance?
Homework Equations
vf^2 = vi^2 + 2ad
Ee = Ek - Eg
The Attempt at a Solution
vf^2 = vi^2 + 2ad
0 = vi^2 + 2ad
2(9.8)(0.95) = vi^2
4.32 m/s = vi
Ee = Ek - Eg
Ee = 0.5mv^2 - mgh
Ee = (0.5)(0.55)(4.32)^2 – (0.55)(9.8)(3.7)
Ee =
I get a negative number?