- #1
psmitty
- 16
- 0
If a bike is running at v=0.866c, and it travels path of length L in time T, when observed from the stationary frame, same path will have length L/2 and be traveled in time T/2 in his, moving frame (because gamma=2 for v=0.866c).
Now, what I don't understand is:
If the bike is not contracted in his (moving) frame and its wheels have a circumference C, that means that its wheels will make L/(2C) turns in this frame.
So, how can they make the same number of turns in the stationary frame, when wheels are contracted, and path is twice the length?
Now, what I don't understand is:
If the bike is not contracted in his (moving) frame and its wheels have a circumference C, that means that its wheels will make L/(2C) turns in this frame.
So, how can they make the same number of turns in the stationary frame, when wheels are contracted, and path is twice the length?