Induced Current in a Circuit by a Moving Magnet

[samee]

A 10-cm-wide, zero-resistance slide wire is pushed toward a 2.0 ohm resistor at a steady speed of 0.50 m/s. The magnetic field strength is 0.50 T. How much power does the pushing force, 6.25*10^-4 supply to the wire? What is the magnitude of the induced current?

I got 3.13*10^-4 for the first part, which is probably correct because it's a simple formula. Just the pushing force times the velocity. However, I cannot figure out how to determine the second part of the question.

I=V/R

While R is given, V is not because it's an induced current. I'm so confused. Help please?

 

[rl.bhat]

Motional EMF produced across the slide wire is given by E = vBL and the induced current I = E/R = vBL/R

 

[ogb p]

Based on the information provided, the magnitude of the induced current can be calculated using the equation V = B*l*v, where B is the magnetic field strength, l is the length of the wire, and v is the velocity. In this case, the length of the wire is not given, but we can assume it is equal to the width of the wire (10 cm). Therefore, the induced voltage can be calculated as V = (0.50 T)(0.10 m)(0.50 m/s) = 0.025 V.

Using Ohm's Law, we can then calculate the magnitude of the induced current as I = V/R = (0.025 V)/(2.0 ohms) = 0.0125 A.

So, the induced current in the circuit is 0.0125 A and the power supplied by the pushing force is 3.13*10^-4 W. It is important to note that this is the power supplied to the wire, not the power dissipated in the resistor. To calculate the power dissipated in the resistor, we would need to know the resistance of the wire as well.