Force required to overcome conveyor PLI belt tension?

[Scoots6]

Force required to overcome conveyor PLI belt tension?

I'm designing a conveyor. A very large one i might add. The conveyor has 3 rolls, one driven and 2 idlers. (kind of shaped like a right triangle)
There is of course a belt (103.5" wide) tensioned at 15PLI. So I know that there are 1552.5lbs of tension across the idler face. Side "A" of the roll is fixed with a spherical roller bearing while side "B" also has a spherical roller bearing but that bearing is mounted on a linear bearing and guide. This is going to allow tram adjustment of the roll to steer the conveyor belt if it decides to walk off.
My concern is determining the amount of force required to HOLD, PUSH, and PULL side "B" of the roll. Given the values I know above, what formula/formulas do I need?
Am I making this much more complicated than it really is?
Please help!

 

[Navin A S]

The force required to overcome the belt tension will depend on the coefficient of friction of the material being moved by the conveyor belt. This coefficient of friction is a measure of how much force is needed to keep the material moving. Generally, higher coefficients of friction require more force to move the material. Therefore, you would need to calculate the total force required to move the material along the conveyor belt, taking into account the coefficient of friction of the material and the tension of the conveyor belt.