- #1
Stingarov
- 22
- 0
Alright so I thought I understood this well.
I'll give an example of how I solve for range and such with the given information:
A ball is thrown from a height of 1.86 m, at a speed of 21 m/s and at an angle of elevation of 59.4o. How far from the person who threw it does the ball land?
Range: Vxt
Vx: Vcos Theta
Vy: V sin Theta
The method in which I solve for t goes as follows:
Vy = 21 * sin59.4
Vy = 18.07
Maximum Height: v²= 2a(s) +existing height of 1.86
Maximum height: 18.07² /2(9.8) = s -> 16.66 + 1.86 = 18.52m
Total time: Time down + Time Up
s + 1.86 = 1/2at² + s = 1/2at²
18.52*2 / 9.8 = t² + 16.66 * 2/9.8 = t²
1.94 + 1.84 = 3.78s
R = V cos Theta * t
R = ~40.4 m
The problem I encounter is simply that I do not know how, using this method, or by any other really, to compute the angle or initial velocity if Total time is not a given already.
Say the equation was rearranged and said:
A person threw the ball at an initial rate of 21 m/s from a height 1.86. It hit the ground at 40.4m. What was the angle of projection?
Can anyone help show me how to work these backwards? Would be highly appreciated.
I'll give an example of how I solve for range and such with the given information:
A ball is thrown from a height of 1.86 m, at a speed of 21 m/s and at an angle of elevation of 59.4o. How far from the person who threw it does the ball land?
Range: Vxt
Vx: Vcos Theta
Vy: V sin Theta
The method in which I solve for t goes as follows:
Vy = 21 * sin59.4
Vy = 18.07
Maximum Height: v²= 2a(s) +existing height of 1.86
Maximum height: 18.07² /2(9.8) = s -> 16.66 + 1.86 = 18.52m
Total time: Time down + Time Up
s + 1.86 = 1/2at² + s = 1/2at²
18.52*2 / 9.8 = t² + 16.66 * 2/9.8 = t²
1.94 + 1.84 = 3.78s
R = V cos Theta * t
R = ~40.4 m
The problem I encounter is simply that I do not know how, using this method, or by any other really, to compute the angle or initial velocity if Total time is not a given already.
Say the equation was rearranged and said:
A person threw the ball at an initial rate of 21 m/s from a height 1.86. It hit the ground at 40.4m. What was the angle of projection?
Can anyone help show me how to work these backwards? Would be highly appreciated.