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heartofaragorn
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Homework Statement
A workman drops a wrench over the side of a high-rise building. Someone looking out their window sees the wrench appear at 11:00 a.m. Another person in an office 25.0 m below the first observer sees the wrench appear exactly 1.00 second after 11:00 AM.
Calculate the instantaneous velocity of the wrench when it passes the second observer, calculate the total distance the wrench has fallen from the point when it passes the second observer, and calculate the time when the wrench was dropped.
Homework Equations
Instantaneous velocity = change in velocity / change in time
v = v initial + accleration X time
x - x initial = v initial X t + 1/2 acceleration X time squared
The Attempt at a Solution
It seemed to me that the instantaneous velocity would be 25 m/s squared, but since that answer is too simple, I'm pretty sure it's wrong. I looked through the kinematic formulas but couldn't find one that I had enough information for. For instance, how do I calculate this using only on measurement (the 1.00 second it took to go 25 m?). Please help!