- #1
NyteBlayde
- 25
- 0
Sorry if the title is a bit vague :/
The Problem: Find the point on the parabola y=1-x^2 at which the tangent line cuts from the first quadrant a triangle with the smallest area.
Relevant Equations: y = 1-x^2 ; y' = -2x ; A= 1/2bh
I'm basically stuck near square one, I found this site through a google search of the above problem and found a similar topic here, but it wasn't quite the same (or at least I didn't see how to relate my problem to it) so I'd like to ask someone to help me out here :)
What I have so far is that the derivative of the tangent line to the curve is -2x. Where should I go from here?
The Problem: Find the point on the parabola y=1-x^2 at which the tangent line cuts from the first quadrant a triangle with the smallest area.
Relevant Equations: y = 1-x^2 ; y' = -2x ; A= 1/2bh
I'm basically stuck near square one, I found this site through a google search of the above problem and found a similar topic here, but it wasn't quite the same (or at least I didn't see how to relate my problem to it) so I'd like to ask someone to help me out here :)
What I have so far is that the derivative of the tangent line to the curve is -2x. Where should I go from here?