- #1
moo5003
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Question:
"A uniform rod of mass m and length 2a stands vertically on a rough horizontal floor and is allowed to fall. Assuming that slipping has no occured, write the angular velocity of the rod as a function of the angle Theta the rod makes with the vertical."
WORK DONE:
Ic = (ml^2)/3
Torque = mgd
d = asin(theta)
Torque = angular accel * I
mgasin(theta) = ang accel * (ml^2)/3
l = 2a
gasin(theta) = ang accel * (m(2a)^2)/3
gsin(theta) = 4/3 * ang acell * a
Ang Accel = 3/(4a) * gsin(theta)
MAIN QUESTION: How do I substitute Angular Acceleration such that I can find an equation that solves angular velocity?
"A uniform rod of mass m and length 2a stands vertically on a rough horizontal floor and is allowed to fall. Assuming that slipping has no occured, write the angular velocity of the rod as a function of the angle Theta the rod makes with the vertical."
WORK DONE:
Ic = (ml^2)/3
Torque = mgd
d = asin(theta)
Torque = angular accel * I
mgasin(theta) = ang accel * (ml^2)/3
l = 2a
gasin(theta) = ang accel * (m(2a)^2)/3
gsin(theta) = 4/3 * ang acell * a
Ang Accel = 3/(4a) * gsin(theta)
MAIN QUESTION: How do I substitute Angular Acceleration such that I can find an equation that solves angular velocity?