- #1
mr_coffee
- 1,629
- 1
For the circuit of Figure 30-19, assume that EMF= 14.0 V, R = 5.40 , and L = 5.00 H. The battery is connected at time t = 0.
Picture:
http://www.webassign.net/hrw/hrw7_30-19.gif
Okay i know there is a simple formula to find the:
(a) How much energy is delivered by the battery during the first 2.00 s?
J
but i don't know where it is, anyone know it?
Also I tried part (b) and got it wrong for some reason:
How much of this energy is stored in the magnetic field of the inductor?
wrong check mark J
I used:
V = iR.
Ub = .5L*i^2;
i = 14/5.40 = 2.59 Amps
Ub = .5*5.00*2.59^2 = 16.77 but they didn't like that at all, any ideas?
thanks.
Picture:
http://www.webassign.net/hrw/hrw7_30-19.gif
Okay i know there is a simple formula to find the:
(a) How much energy is delivered by the battery during the first 2.00 s?
J
but i don't know where it is, anyone know it?
Also I tried part (b) and got it wrong for some reason:
How much of this energy is stored in the magnetic field of the inductor?
wrong check mark J
I used:
V = iR.
Ub = .5L*i^2;
i = 14/5.40 = 2.59 Amps
Ub = .5*5.00*2.59^2 = 16.77 but they didn't like that at all, any ideas?
thanks.