- #1
mtayab1994
- 584
- 0
Homework Statement
Look at the attachment
Please tell me if there is anything wrong with my work because apparently my teacher thinks its wrong.
Doc Al said:Can you please state the problem and what you are asked to find?
Doc Al said:I'm a bit puzzled by the problem. You are given both the distance traveled and the speed at point B? (Seems like you should be able to calculate the speed given the distance.)
Doc Al said:I'm a bit puzzled by the problem. You are given both the distance traveled and the speed at point B? (Seems like you should be able to calculate the speed given the distance.)
I did not solve for the speed myself, but it seems as if you're saying that it comes out to be 2 m/s. Yet on your sheet it seems to be given as 3 m/s. Something's wrong somewhere.mtayab1994 said:yea i did solve it and it came out to 2m/s and everything else is correct and i don't know how my teacher thinks its wrong.
Once again I ask: Are you given both the distance AB and the speed at point B? (If so, you should check that the speed at B is correct by solving for it directly.)mtayab1994 said:No that speed is for when the body is at the point B.
Doc Al said:Once again I ask: Are you given both the distance AB and the speed at point B? (If so, you should check that the speed at B is correct by solving for it directly.)
Malor said:For the speed at point B try the following:
EpotA = EkinB
mgh = m/2*v²
v = sqrt(2gh) (h=0,5m)
Check what you did differently, and that's where you went wrong.
Did you check that Vb = 3 m/s is correct? My point is that given AB = 1m, you should be able to solve for Vb. They shouldn't have to give it to you.mtayab1994 said:Yes i am given AB=1m and Vb=3m/s but the question was to find the speed at the point C.
Doc Al said:Did you check that Vb = 3 m/s is correct? My point is that given AB = 1m, you should be able to solve for Vb. They shouldn't have to give it to you.
Assuming that the speed at B is correct, then the speed you calculated for point C seems correct to me.mtayab1994 said:Ok i'll check the speed at b right now and we given the speed at the point b so we can use it to find the speed at c and is my speed for c correct?
Doc Al said:Assuming that the speed at B is correct, then the speed you calculated for point C seems correct to me.
Malor said:deleted
mtayab1994 said:deleted what?
With
Erad = 1/2 Jω², ω=v/b, b=2/6∏r
EkinB - Erad - EpotC = EkinC
=> vB²-2r²(v²/((2/6)∏r)²-2gh=v² => v=1.32m/s says my calculator
Malor said:I deleted something that I thought made no sense and replaced it with what I think the answer to be ;p
h = cos 60 * r
Because at point C, the object has kinetic, potential and rotational Energy.
Kinetic energy is the energy an object possesses due to its motion. It is defined as the product of an object's mass and the square of its velocity. The faster an object moves, the more kinetic energy it has. This energy can be transferred from one object to another through collisions or can be converted into other forms of energy, such as heat.
Potential energy is the energy an object possesses due to its position or state. It is stored energy that can be converted into kinetic energy. The two types of potential energy are gravitational potential energy, which is based on an object's height and mass, and elastic potential energy, which is based on an object's deformation from its original shape.
Work is the transfer of energy from one object to another. When a force is applied to an object and causes it to move, work is being done and the object gains kinetic energy. Similarly, when an object is lifted or stretched, work is being done against gravity or an elastic force, and the object gains potential energy.
Yes, kinetic energy and potential energy are interchangeable. Kinetic energy can be converted into potential energy and vice versa. For example, a roller coaster car gains kinetic energy as it moves down a hill, but as it reaches the top of the next hill, that kinetic energy is converted into potential energy due to its increased height. This conversion continues as the roller coaster moves along the track.
Temperature and speed are directly related to an object's kinetic energy. As the temperature of an object increases, the particles within it move faster, resulting in an increase in kinetic energy. Similarly, as an object's speed increases, its kinetic energy also increases. This is because the kinetic energy is dependent on the square of the object's velocity, meaning that even a small increase in speed can result in a significant increase in kinetic energy.