- #1
Taturana
- 108
- 0
Hi.
I differentiated the equation of kinetic energy
[tex]E(v) = \tfrac{1}{2} mv^2[/tex]
and I got:
[tex]E'(v) = mv[/tex].
I'm new to the concept of derivatives so I only know that it means that m*v is the slope of a tangent line to the graph of E at a given point.
But I can't really understand the exact meaning of it (if there are any).
Could someone explain me more about this?
Thank you
I differentiated the equation of kinetic energy
[tex]E(v) = \tfrac{1}{2} mv^2[/tex]
and I got:
[tex]E'(v) = mv[/tex].
I'm new to the concept of derivatives so I only know that it means that m*v is the slope of a tangent line to the graph of E at a given point.
But I can't really understand the exact meaning of it (if there are any).
Could someone explain me more about this?
Thank you