Two successive digits and divisibility puzzle

In summary, the possible values for an 8-digit base 10 positive integer that satisfy the given conditions are 18495632 and 78495632.
  • #1
K Sengupta
113
0
Determine all possible value(s) of a 8-digit base 10 positive integer having the form ABCDEFGH, where each of the capital letters denotes a different digit from 1 to 9, that satisfy each of the following conditions:

(I) AB is divisible by 2, and:

(II) BC is divisible by 6, and:

(III) CD is divisible by 7, and:

(IV) DE is divisible by 5, and:

(V) EF is divisible by 8, and:

(VI) FG is divisible by 9, and:

(VII) GH is divisible by 4
 
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  • #2
B C F H @ [2 4 6 8]
A D G @ [1 3 7 9]

DE/5 -> E=5
EF/8 -> EF=56-> F=6
FG/9 -> FG=63-> G=3
GH/4 -> GH=32-> H=2

A D @ [1 7 9]
B C @ [4 8]

CD/7 -> CD=49-> C=4, D=9, B=8
AB/2 -> A=1,7

ABCDEFGH=18495632, 78495632
:smile:
 

1. How does the "Two successive digits and divisibility puzzle" work?

The puzzle involves finding a number that is divisible by both of its two-digit numbers formed by the first two digits and the last two digits. For example, if the number is 12345, it should be divisible by 12 and 45.

2. What is the general strategy for solving this puzzle?

The general strategy is to first identify the two-digit numbers formed by the first two digits and the last two digits of the given number. Then, find the common factors of these two numbers. The number will be divisible by both of these two-digit numbers if it is divisible by their common factors.

3. Is there a specific method for finding the two-digit numbers in the puzzle?

Yes, the two-digit numbers can be found by using the formula n(n+1), where n is the first digit of the given number. For example, if the number is 12345, the two-digit numbers would be 12 (1*2) and 45 (9*5).

4. Can this puzzle have multiple solutions?

Yes, there can be multiple solutions for this puzzle. However, some numbers may not have any solution at all.

5. Are there any other variations of this puzzle?

Yes, there are variations where the number is divisible by the two numbers formed by the first three digits and the last three digits, or even the first four digits and the last four digits. The same strategy can be applied to solve these variations.

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