- #1
optics.tech
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Hi everyone,
Can you tell me how to integrate the following equation?
[tex]\int\frac{1}{x^2 + 1} \ dx[/tex]
I've tried the substitution method, u = x^2 + 1, du/dx = 2x. But the x variable is still exist.
Also, the trigonometry substitution method, but the denominator is not in [tex]\sqrt{x^2 + 1}[/tex] form.
Thanks in advance
Huygen
Can you tell me how to integrate the following equation?
[tex]\int\frac{1}{x^2 + 1} \ dx[/tex]
I've tried the substitution method, u = x^2 + 1, du/dx = 2x. But the x variable is still exist.
Also, the trigonometry substitution method, but the denominator is not in [tex]\sqrt{x^2 + 1}[/tex] form.
Thanks in advance
Huygen