- #1
MarekS
- 34
- 0
Hello!
There's a combination exercise that has been bewildering me for some time now: how many divisors does the number 378 have?
I know it can be done like this: 378=2x3x3x3x7.
Divisors are as follows: 1,2,3,6,7,9,12,14,18,21,42,54,63,126,189,378. 16 all together.
But, in essence, it has to be a combinations task, the only catch is that the element 3 is recurrent.
Is there a formula that takes this aspect into account?
MarekS
There's a combination exercise that has been bewildering me for some time now: how many divisors does the number 378 have?
I know it can be done like this: 378=2x3x3x3x7.
Divisors are as follows: 1,2,3,6,7,9,12,14,18,21,42,54,63,126,189,378. 16 all together.
But, in essence, it has to be a combinations task, the only catch is that the element 3 is recurrent.
Is there a formula that takes this aspect into account?
MarekS