- #1
theown1
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A carnot engine has an efficiency of 59% and performs 2.5x104 J of work in each cycle. a) how much heat does the engine extract from its heat source in each cycle?
b) suppose the engine exhausts heat at room temp (20oC) what is the temperature of the heat source?
I know that the efficiency of a heat engine is e=W/Qh or for a carnot engine e =1-Tc/Th
3. solution
I managed to find the solution for the first part which was 0.59=W/Th(W=2.5x104J)
and I just solved for Th which came out to be 4.2x104J
but I'm not sure how I go about solving for part b, I was thinking that since it said the engine exhausts heat at room temp, so does that mean that Th-Tc=20? or do I have to convert that temperature to internal energy and solve? I'm not sure I'm pretty confused on what it means, can anyone help
b) suppose the engine exhausts heat at room temp (20oC) what is the temperature of the heat source?
I know that the efficiency of a heat engine is e=W/Qh or for a carnot engine e =1-Tc/Th
3. solution
I managed to find the solution for the first part which was 0.59=W/Th(W=2.5x104J)
and I just solved for Th which came out to be 4.2x104J
but I'm not sure how I go about solving for part b, I was thinking that since it said the engine exhausts heat at room temp, so does that mean that Th-Tc=20? or do I have to convert that temperature to internal energy and solve? I'm not sure I'm pretty confused on what it means, can anyone help