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darkar
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How do u expand f(x,y) = y^2/x^2 about the point (1,-1) ? up to and including quadratic term?
Have you ever used the taylor series on multi-variable functions before?darkar said:How do u expand f(x,y) = y^2/x^2 about the point (1,-1) ? up to and including quadratic term?
The domain of the function is all real numbers except for x = 0, as dividing by 0 is undefined.
The range of the function is all non-negative real numbers, as y^2 and x^2 are always positive or zero.
Yes, this function is symmetric about the y-axis. This means that if we reflect the graph of the function across the y-axis, it will still be the same.
Yes, there is one critical point at (0,0). This is because the derivative of the function is undefined at this point.
As x approaches infinity, the graph of the function approaches the x-axis. As y approaches infinity, the graph of the function approaches the line x=0.