- #1
matti0827
- 1
- 0
Homework Statement
A regulation basketball net is 3.05 m above the floor. The three point
circle is about 4.6 metres from the basket- the player 5.0 m. At what speed should
the player shoot if the ball is released at a height of 2.25 m at 45 above the horizontal
to score three points?
dy= 3.05m - 2.25m = +0.8m
dx= 5.0 m
a=g=-9.8 m/s2
angle= 45
Homework Equations
∆dy= v1ysin45 ∆t + 1/2 g∆t2
∆dx= v1xcos45 ∆t
The Attempt at a Solution
do I not need time?