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ayesha91
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Homework Statement
Elevator cabs A and B are connected by a short cable and can be pulled upward or lowered by the cable above cab A. Cab A has mass 1700 kg; cab B has mass 1300 kg. A 12.0 kg box of catnip lies on the floor of cab A. The tension in the cable connecting the cabs is 1.91×10^4 N. What is the magnitude of the normal force on the box from the floor?"
Homework Equations
F=ma
The Attempt at a Solution
T-mBg=mBa
T = mB(a+g)
a+g=T/mB
N=m(a+g) = m (T/mB)= (12.0)(1.91×10^4/1300) = 176 N (rounded value)