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Homework Statement
Consider a submarine cruising 32 ft below the free surface of seawater whose density is 64 lbm / (ft^3). What is the increase in the pressure in psi exerted on the submarine when it dives to a depth of 172 ft below the free surface? Assume that the acceleration due to gravity is 32.4 ft/(s^2)
Homework Equations
P = Rho *g * h
The Attempt at a Solution
I am used to metric units and this is in english units.
I muliply 140 ft. (change in depth) by 64 (lb (mass)/ (m^3)) (density) by 32.4 ft/s^2 (gravity)
The answer should be in psi, but I get units of (lbm / ft * s^2)
God I loathe English units.