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mack2014
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I am working on a lab that is meant to test the validity of (m1
How did you get this relation? Is it a typo?(m1 m2)g=(m1 +m2 + I/R^2 )a
... which shows a great deal of confusion.I thought that at first but my mass for m1 is 0.11975kg and m2 is 0.11975kg. They add to 0.23385kg which is much greater then .2109... I thought my graph may have been backwards, but the directions indicate that I am to plat (m1 - m2)g on the Y axis and acceleration on the x. Also, we aren't given R and although I can measure it, there is no mention of measuring the pulley to find it
While ##m_1## and ##m_2## are not held constant, ##M=m_1+m_2## is a constant if you varied the masses by moving a weight from one side of the machine to the other.I thought that at first but my mass for m1 is 0.11975kg and m2 is 0.11975kg. They add to 0.23385kg which is much greater then .2109...
You should always make sure you understand the reasons for the instructions. If you just follow them blindly in the lab, then you will make mistakes.I thought my graph may have been backwards, but the directions indicate that I am to plat (m1 - m2)g on the Y axis and acceleration on the x.
The lab instruction do not always tell you absolutely everything you must do - you are expected to be able to figure out the basic stuff yourself. Notice that your theoretical line needs a value for R ... unless you know another relation involving R that you can use to cancel it out of course?Also, we aren't given R and although I can measure it, there is no mention of measuring the pulley to find it
Were you able to derive this equation algebraically - i.e. via a free-body diagram?Thank you for the response, I am working through it now. We are actially given
(m1 m2)g=(m1 +m2 + I/R^2 )a in the lab. The whole point of the lab is to derive this equation..
... good, how did you vary m1 and m2. That was the important part of the question.I did vary m1 and m2 to produce different acceleration rates.
Simon Bridge said:You may need to comment on the fact you got a non-zero y-intercept when the theory predicts it should be zero.
What does this mean, if anything?
An Atwood pulley is a simple machine consisting of a grooved wheel and a rope or belt that can be used to lift or move objects. It is named after its inventor, George Atwood, and is commonly used in physics experiments to demonstrate concepts such as inertia and acceleration.
An Atwood pulley operates on the principle of conservation of energy. The weight of the object on one side of the pulley is balanced by the weight of the counterweight on the other side, resulting in a net force of zero. This allows the object to move at a constant velocity, unless acted upon by an external force.
Slope (m) is a measurement of the steepness or incline of a line on a graph. In the context of calculating inertia, it refers to the slope of the velocity vs. time graph of an object in motion. The steeper the slope, the greater the acceleration and therefore the greater the inertia of the object.
The formula for calculating inertia based on slope (m) is inertia = mass x slope. This formula takes into account the mass of the object and the steepness of the slope on the velocity vs. time graph. The higher the mass and/or the steeper the slope, the greater the inertia of the object.
Inertia is a fundamental concept in physics that describes an object's resistance to change in motion. Understanding inertia allows scientists to predict and explain the behavior of objects in motion, and it is crucial in fields such as mechanics, engineering, and astronomy.