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NoScale model F-local term

by ChrisVer
Tags: flocal, model, noscale, term
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ChrisVer
#1
Jun19-14, 07:01 PM
P: 739
In case you have the Kahler and super- potential [itex]K,W[/itex]:

[itex] K(T,S,C) = -log (S +S^{*}) -3 log ( T+ T^{*} - C C^{*}) [/itex]
[itex] W(T,S,C)= C^{3} + d e^{-aS} +b [/itex]

with [itex]T,S,C[/itex] chiral super fields, [itex]b,d[/itex] complex numbers and [itex]a>0[/itex].
I tried to calculate the local F-terms arising from this. The local F-terms for the i-th chiral superfield are given by:

[itex] F_{i}= D_{i}W = K_{i}W + W_{i}[/itex]

where in the rhs the index i denotes the derivative wrt to the i-th field. eg [itex]W_{S}=\frac{\partial W}{\partial S}[/itex]

However I'm having a slight problem with the particular derivative. See what I mean...taking it:

[itex] F_{S}= K_{S} W + W_{S} = - \frac{C^{3} + d e^{-aS} +b}{S+S^{*}} -d a e^{-aS}[/itex]

correct?
On the other hand, if I try to work with the covariant derivative wrt to the conjugate fields:

[itex] F^{*}_{S}= D_{S^{*}} W^{*} = K_{S^{*}} W^{*} + W_{S^{*}} [/itex]
I don't get the complex conjugate of the above. Because in this case
[itex]W_{S^{*}}=0[/itex]
and so:

[itex] F^{*}_{S}= - \frac{(C^{3} + d e^{-aS} +b)^{*}}{S+S^{*}}[/itex]

what's the problem?
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ChrisVer
#2
Jun19-14, 07:05 PM
P: 739
Ah found the mistake.... again by writing in LaTeX it became obvious- In the F* equation I needed the W* derivative as the second term...
However
In the case of [itex]F[/itex] let's say... How can I see if its module squared is simultaneously zero or not?

[itex] |F_{T}|^{2}= \frac{9}{(T+T^{*} - CC^{*})^{2}} |C^{3}+ d e^{-aS} +b |^{2} [/itex]

[itex] |F_{S}|^{2}= | \frac{C^{3} + d e^{-aS} +b}{S+S^{*}} + d a e^{-aS}|^{2} [/itex]

[itex] |F_{C}|^{2}= | \frac{3 C^{*} (C^{3}+d e^{-aS} +b)}{T+T^{*}-CC^{*}} +3 C^{2}|^{2} [/itex]


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