- #1
1MileCrash
- 1,342
- 41
63.8 mg of a C - H - O compound produces 145.0 mg of CO2 and 59.38 mg of H2O. Find empirical formula.
I THOUGHT that I simply had to find the moles of each compound as a ratio, but in doing that I get an answer that isn't an option.
I calculate moles C as (12/44)(.145) = .0395 grams carbon = .00329 moles carbon
Moles O as .10546 grams + .052 grams = .0097 moles oxygen
Moles H as .00329 moles H
Or CO3H...
What am I doing wrong here? I can't remember this crap.
I THOUGHT that I simply had to find the moles of each compound as a ratio, but in doing that I get an answer that isn't an option.
I calculate moles C as (12/44)(.145) = .0395 grams carbon = .00329 moles carbon
Moles O as .10546 grams + .052 grams = .0097 moles oxygen
Moles H as .00329 moles H
Or CO3H...
What am I doing wrong here? I can't remember this crap.