- #1
hant
- 1
- 0
Hello, I have a simple question.
When reducing a lambda expression what happens in this case:
(L x.y) (L z.z) (L z.z) -> y (L z.z) right?
How to interpret the variable y in front? Is that normal form, or can
I reduce it to just: y
Or is the expression ilegal?
Thanks
When reducing a lambda expression what happens in this case:
(L x.y) (L z.z) (L z.z) -> y (L z.z) right?
How to interpret the variable y in front? Is that normal form, or can
I reduce it to just: y
Or is the expression ilegal?
Thanks