- #1
psycovic23
- 48
- 0
I have a question in my textbook that I can't answer for the life of me.
"A 6500-kg helicopter accelerates upward at .6 m/s^2 while lifting a 1200-kg car. (a) what is the lift force exerted by the air on the rotors?"
Now, my diagram has a vector pointing up with a force of (6500*9.8)N. There is also a vector pointing down at (1200*9.8)N. Wouldn't the net force then be equal to the force of the pull minus the force of the weight? Fn-(6500*9.8)-(1200*9.8) = net force
Or am I completely wrong? At the moment, having read this section multiple times, I'm still having trouble grasping this whole natural force and the summation of the forces = ma. My teacher doesn't really help much as she isn't the greatest teacher either...
"A 6500-kg helicopter accelerates upward at .6 m/s^2 while lifting a 1200-kg car. (a) what is the lift force exerted by the air on the rotors?"
Now, my diagram has a vector pointing up with a force of (6500*9.8)N. There is also a vector pointing down at (1200*9.8)N. Wouldn't the net force then be equal to the force of the pull minus the force of the weight? Fn-(6500*9.8)-(1200*9.8) = net force
Or am I completely wrong? At the moment, having read this section multiple times, I'm still having trouble grasping this whole natural force and the summation of the forces = ma. My teacher doesn't really help much as she isn't the greatest teacher either...