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menager31
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There is a base-quadrilateraled pyramid ABCDS , which base is quadrilateral ABCD. Inscribed sphere is tangent in point P on the ABCD wall. Proof that
<)APB+<)CPD=180'
I don't like geometry and i really don't know how to start.
<)APB+<)CPD=180'
I don't like geometry and i really don't know how to start.