- #1
DeadxBunny
- 30
- 0
Space Curves --> Unit Tangent Vector and Curvature
Here is the original question:
Consider the space curve r(t) = (e^t)*cos(t)i + (e^t)*sin(t)j + k. Find the unit tangent vector T(0) and the curvature of r(t) at the point (0,e^(pi/2),1).
I believe I have found the unit tangent vector, T(0), correctly: (1/sqrt(2))i + (1/sqrt(2))j
Is this correct? Also, how do I find the curvature at that particular point?
Thanks!
Here is the original question:
Consider the space curve r(t) = (e^t)*cos(t)i + (e^t)*sin(t)j + k. Find the unit tangent vector T(0) and the curvature of r(t) at the point (0,e^(pi/2),1).
I believe I have found the unit tangent vector, T(0), correctly: (1/sqrt(2))i + (1/sqrt(2))j
Is this correct? Also, how do I find the curvature at that particular point?
Thanks!