- #1
tahayassen
- 270
- 1
Let f(x)=(x)^(x)
f(-1)=(-1)^(-1)
=1/-1
=-1
But according to wolframalpha, f(-1) does not exist.
f(-1)=(-1)^(-1)
=1/-1
=-1
But according to wolframalpha, f(-1) does not exist.