- #1
aisha
- 584
- 0
[tex] 16x^2+9y^2+192y-36y+468=0 [/tex]
Was the original conic i had to conver this into standard form and got
[tex] \frac {(x+6)^2} {9} + \frac {(y-2)^2} {16} =1 [/tex]
Im not sure if this is a horizontal or vertical ellipse
Was the original conic i had to conver this into standard form and got
[tex] \frac {(x+6)^2} {9} + \frac {(y-2)^2} {16} =1 [/tex]
Im not sure if this is a horizontal or vertical ellipse