- #1
JamesJames
- 205
- 0
Will P(r) depend on time? Explain your reasoning.
The wavefunction is
[tex]
\frac{1}{\sqrt{2}} (\psi_{2,1,-1}+\psi_{2,1,1})
[/tex]
[tex]
\frac{1}{16}\,{\frac {r{e^{-1/2\,ra}}\sin \left( \theta \right) \left( {e^{-i
\phi}}-{e^{i\phi}} \right) \sqrt {2}\sqrt {{\pi }^{-1}}}{\sqrt {{a}^{3
}}a}}
[/tex]
Guys, this is really urgent and I am genuinely lost here...any help would be really appreciated. I can show why P(r) does not depend on time quite easily but how do I show or explain that P(r) depends/does not depend on time?
Please guys, I really need the help.
James
The wavefunction is
[tex]
\frac{1}{\sqrt{2}} (\psi_{2,1,-1}+\psi_{2,1,1})
[/tex]
[tex]
\frac{1}{16}\,{\frac {r{e^{-1/2\,ra}}\sin \left( \theta \right) \left( {e^{-i
\phi}}-{e^{i\phi}} \right) \sqrt {2}\sqrt {{\pi }^{-1}}}{\sqrt {{a}^{3
}}a}}
[/tex]
Guys, this is really urgent and I am genuinely lost here...any help would be really appreciated. I can show why P(r) does not depend on time quite easily but how do I show or explain that P(r) depends/does not depend on time?
Please guys, I really need the help.
James
Last edited: